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Nataly [62]
2 years ago
10

1%7D%7Bn%5E%7B3%7D%7D%2C..." id="TexFormula1" title="1,\frac{1}{8},\frac{1}{27},\frac{1}{64},...,\frac{1}{n^{3}},..." alt="1,\frac{1}{8},\frac{1}{27},\frac{1}{64},...,\frac{1}{n^{3}},..." align="absmiddle" class="latex-formula">
The denominator of the seventh term is
A.] 125
B.] 216
C.] 343
D.] 513
Mathematics
1 answer:
Alex2 years ago
5 0
Answer: option C) 343

Justification:

The sequence of the denominators is:

term         denominator

1               1 = 1^3
2               8 = 2^3
3               27 = 3^3
4               64 = 4^3

5               5^3 = 125
6               6^3 = 216
7               7^3 = 343

And that is the term searched. So, the answer is the option C) 343.
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