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Agata [3.3K]
2 years ago
11

-7x+4= 18 set notation interval notation

Mathematics
1 answer:
denpristay [2]2 years ago
7 0

Answer:

Step-by-step explanation:

-7x+4=18

-7x=14

Divide-7 on both sides of the equal sign which is going to leave you with x=-2

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A box is in the shape of a right rectangular prism. The base of the box has an area of 15 square inches. The height of the box i
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The answer is 180cubic2 (square)
7 0
3 years ago
4y + 12 = 7 - 5y thank you :)
riadik2000 [5.3K]
Y= -5 i am pretty sure
3 0
3 years ago
Read 2 more answers
Helpppp quickk pleassee I’m being timeddd
Alex

<u>Given</u>:

The given graph represents the cost of the Kayak's rental per hour.

The coordinates are (2,30) and (3,45)

We need to determine the unit rate of renting per hour.

<u>Unit rate of renting:</u>

The unit rate of renting can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the coordinates (2,30) and (3,45), we get;

m=\frac{45-30}{3-2}

Simplifying, we get;

m=\frac{15}{1}

Dividing, we get;

m=15

Thus, the unit rate for renting a Kayak is $15 per hour.

7 0
3 years ago
In the expression 2(10x) + 15y, x represents the number of hours Nina works in a week at a clothing store and y represents the n
ale4655 [162]

Answer:

The statement which is true in the choices is the third item in the choices such as "Nina makes 20x dollars at the clothing store each week". It was clearly stated in the given that x represent the total number of hours she worked in a week. This statement made the other items in the choices wrong.

Step-by-step explanation:

I hope this helps you :)

6 0
3 years ago
Read 2 more answers
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
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