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3 years ago

Solve the simultaneous equations x − y = −1 and 2x − y = 0

Mathematics

1 answer:

densk [106]3 years ago

3 0

Answer:

X=1, y=2

Step-by-step explanation:

Use the first equation minus the second equation:

(x-2x)-(y-(-y))=-1

-x=-1

x=1

1-y=-1

y=2

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If f(x)=5x^3 and g(x)=x+1, find (f•g)(x)

alukav5142 [94]

Hello from MrBillDoesMath!

Answer:

5 x^3 + 15 x^2 + 15 x + 5 , none of the provided choices

Discussion:

f(x) = 5 x^3

g(x) = x+ 1

(f•g)(x) =

f(g(x)) =

f(x+1) =

5 * (x+1)^3 =

5 x^3 + 15 x^2 + 15 x + 5

which is none of the provided answers.

Thank you,

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3 years ago

1--1/3(-3) + 4(1)+12=3(-3)

igor_vitrenko [27]

Answer:

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Step-by-step explanation:

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3 years ago

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Simplify by dividing negative three over eight divided by five over nine.

goblinko [34]

Answer:

$\frac{-27}{40}$

Step-by-step explanation:

First we need to write in correct form :

$\frac{-3}{8}:\frac{5}{9}$

We know how to divide fractions. If we can divide numerator by numerator, denominator by denominator, we just do it. In this example we can not do that.

So, we rewrite first fraction and multiply by reciprocal second ( numerator and denominator change place)

$\frac{-3}{8} *\frac{9}{5}$

Now, multiply numerator by numerator, denominator by denominator :

$\frac{-27}{40}$

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Image of problem attached

AlexFokin [52]

Answer:

g(x)=f(x+1)

h(x)=f(x)+3

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2 years ago

Pls, Help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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I can help you if you still!!!

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