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2 years ago

Please help me please i really need help

Mathematics

2 answers:

Fantom [35]2 years ago

6 0

Answer:

Step-by-step explanation: It you start by getting rid of the 1/2x+1/2x it makes x=x/1. X/1 is x so x=x. X can be anything!

Sedaia [141]2 years ago

4 0

0 = 1 ; no solution.

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lara [203]

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alexgriva [62]

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3 years ago

Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)

Maurinko [17]

Answer:

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

$(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0$

Substituting the end point are

$(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\$

Applying Distributive Property we get

$x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0$

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

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2 years ago

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Ivenika [448]

The answer is C -208 degrees Fahrenheit!

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3 years ago