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ladessa [460]
3 years ago
5

Evaluate 5c+cd5c+cd5, c, plus, c, d when c=\dfrac15c=

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Ignore I want point so I can get answers for freeStep-by-step explanation:

Poopy poop poop

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One day at football practice, Darrell, the kicker, punted the ball so that its height in feet above the ground was given by the
Tju [1.3M]

The height of the all after 2 secs is 86 feet

<h3>Functions and vales</h3>

Given the height in feet above the ground was given by the following function h(t) = -16t^2 + 75t

where:

t is the number of seconds since the ball was punted.

If the value of t = 2s, hence;

h(t) = -16t^2 + 75t

h(2) = -16(2)^2 + 75(2)

h(2) = -64 + 150
h(2) = 86

Hence the height of the all after 2 secs is 86 feet

Learn more about linear equation here: brainly.com/question/14323743

8 0
3 years ago
Hat is the interquartile range of the data represented by the box plot shown below?
marissa [1.9K]

Answer:

Where is the box plot?

Step-by-step explanation:

3 0
4 years ago
Find the circumference of a circle with a diameter of 18 inches
ValentinkaMS [17]

Answer:

39.4384

Step-by-step explanation:

C= 2(pi)(r)

C=2(3.14)(9)

39.4384=2(3.14)(9)

7 0
4 years ago
Read 2 more answers
What is the vertex of a parabola defined by the equation <br> x = 5y2?
QveST [7]

Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0

3 0
4 years ago
Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a
Svet_ta [14]

Answer:

The area that was not painted is (2x^{2}-6x+6)\ units^{2}

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

A=LW

In this problem we have

L=2x-3

W=x

substitute

A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}

step 2

Find the area that was painted

A=(3)(x-2)\\A=(3x-6)\ units^{2}

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}

8 0
3 years ago
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