The height of the all after 2 secs is 86 feet
<h3>Functions and vales</h3>
Given the height in feet above the ground was given by the following function h(t) = -16t^2 + 75t
where:
t is the number of seconds since the ball was punted.
If the value of t = 2s, hence;
h(t) = -16t^2 + 75t
h(2) = -16(2)^2 + 75(2)
h(2) = -64 + 150
h(2) = 86
Hence the height of the all after 2 secs is 86 feet
Learn more about linear equation here: brainly.com/question/14323743
Answer:
Where is the box plot?
Step-by-step explanation:
Answer:
39.4384
Step-by-step explanation:
C= 2(pi)(r)
C=2(3.14)(9)
39.4384=2(3.14)(9)
Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
Answer:
The area that was not painted is 
Step-by-step explanation:
step 1
Find the area of the rectangle
we know that
The area of a rectangle is equal to

In this problem we have


substitute

step 2
Find the area that was painted

step 3
Find the area that was not painted
Subtract the area that was painted from the total area of rectangle
so
