Ask question

Ask question

All categories

3 years ago

14

Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a

nd it has a length of 3 and a width of x-2 .Find the size of the area that was not painted
Help me please

1 answer:

Svet_ta [14]3 years ago

8 0

Answer:

The area that was not painted is $(2x^{2}-6x+6)\ units^{2}$

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

$A=LW$

In this problem we have

$L=2x-3$

$W=x$

substitute

$A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}$

step 2

Find the area that was painted

$A=(3)(x-2)\\A=(3x-6)\ units^{2}$

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

$A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}$

You might be interested in

The table shows the outputs, y, for different inputs, x:

Akimi4 [234]

A Yes as the x values are all different

B f(x) = 5x + 14

when x = 2 , f(x) = 5(2) + 14 = 24
x = 5, f(x) = 39,
Each value of f(x) is greater than corresponding ones in the function in A.
when x = 9 f(x) = 59 which is greater than for first function ( =12)

First function is a decreasing while f(x) is increasing

C f(x) = 64 = 5x + 14

5x = 64 - 14 = 50

x = 10

8 0

3 years ago

For the pair of functions, find the indicated sum, difference, product, or quotient. f(x) = 16 - x2; g(x) = 4 - x Find (f + g)(x

Rudik [331]

(16-x²)+(4-x) or (-x²+16)+(-x+4)

Combine like terms

(-x²+20-x) or (-x²-x+20)

7 0

3 years ago

Read 2 more answers

Please Help! 20 Points!

iVinArrow [24]

$\text {x - coordinate = } \bigg( 5\dfrac{1}{2} + 3\dfrac{3}{4} \bigg) \div 2$

$\text {x - coordinate = } \bigg( 5\dfrac{2}{4} + 3\dfrac{3}{4} \bigg) \div 2$

$\text {x - coordinate = } 8\dfrac{5}{4} \div 2$

$\text {x - coordinate = }\dfrac{37}{4} \times \dfrac{1}{2}$

$\text {x - coordinate = }\dfrac{37}{8}$

$\text {x - coordinate = } 4\dfrac{5}{8}$

$\text {y - coordinate = } \bigg( -4\dfrac{1}{4} - 1\dfrac{1}{4} \bigg) \div 2$

$\text {y - coordinate = } -5\dfrac{2}{4} \div 2$

$\text {y - coordinate = } -\dfrac{22}{4} \times \dfrac{1}{2}$

$\text {y - coordinate = } -\dfrac{11}{4}}$

$\text {y - coordinate = } -2\dfrac{3}{4}}$

$\text {The coordinate is }\bigg( 4\dfrac{5}{8}, -2\dfrac{3}{4}} \bigg)$

6 0

2 years ago

F(x) = 5x + 4<br> g(x) = 5x2 – 7x – 2<br> Find: f(x) · g(x)

weeeeeb [17]

Answer:

$25x^{3}-15x^{2} -38x-8$

Step-by-step explanation:

Multiply the equations together

(5x+4)(5x^2-7x-2)

25x^3-35x^2-10x+20x^2-28x-8

Add like terms

25x^3-15x^2-38x-8

7 0

2 years ago

You have 2\3 of a pizza left from yesterday. You divide it into 4 equal pieces. What fraction of the pizza is each piece?

romanna [79]

<h3>Answer: 1/6</h3>

====================================================

Explanation:

Let's say for example this pizza had 6 slices to start with. Two-thirds of this is (2/3)*12 = 4 slices. So you have 4 slices left over from yesterday. Then let's say you hand one slice to each of your four friends. Each friend would have 1/6 of the original pizza.

4 0

2 years ago