Answer:Option C:
64 \ cm^2 is the area of the composite figure
It is given that the composite figure is divided into two congruent trapezoids.
The measurements of both the trapezoids are
b_1=10 \ cm
b_2=6 \ cm and
h=4 \ cm
Area of the trapezoid = \frac{1}{2} (b_1+b_2)h
Substituting the values, we get,
A=\frac{1}{2} (10+6)4
A=\frac{1}{2} (16)4
A=32 \ cm^2
Thus, the area of one trapezoid is $32 \ {cm}^{2}$
The area of the composite figure can be determined by adding the area of the two trapezoids.
Thus, we have,
Area of the composite figure = Area of the trapezoid + Area of the trapezoid.
Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2
Thus, the area of the composite figure is 64 \ cm^2
Step-by-step explanation:
Answer:
18π ≈ 56.5 meters
Step-by-step explanation:
The length of the arc of a circle is given by the formula ...
s = rθ . . . . where r is the radius, and θ is the central angle in radians
<h3>Application</h3>
You are given the values of r and θ, so you only need to put them into the formula and simplify.
s = (27 m)(2π/3) = 18π m
The length of the arc is 18π meters, about 56.5 meters.
ANSWER: 11.08
EXPLANATION: Add a zero after the 9 to make the number 29.90. Then subtract normally.
Jay walks 2 1/4 miles which if you double it so the denominators are e same for both 2 1/4 and 1 1/8 then your answer will be 18/8 (Jay) and 9/8 (Reggie). Meaning that Reggie walks have the distance Jay walks.
