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denpristay [2]
3 years ago
14

Help please. find the values of x and y and if you feel like it, show your work

Mathematics
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

x=4, y=61

Step-by-step explanation:

Since the triangles are congruent, we already know that they have the same angles and sides.

We can solve for the missing side with this equation:

51=12x+3

<em>subtract</em> 3 from both sides

48=12x

<em>divide </em>both sides by 12

x = 4

Due to the Angle Theorems we already know 2 of the angles on the triangle:

63 and 56

We can solve for the missing angle with this equation:

A+B+C=180

63+56+y=180

119+y=180

<em>subtract </em>119 from both sides

y=61

<em>plz mark me brainliest.</em> :)

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Answer:

Width x height x length

Step-by-step explanation:

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4 0
3 years ago
Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

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1 year ago
CAN smb HELP me please 20 POINTS!!!! and im giving brainly
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Answer:

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Step-by-step explanation:

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