Ask question

Ask question

All categories

3 years ago

9

Write an equation in point slope form that represents the line that passes through the point (-2,-1) and has a slope of 5. Then,

convert the equation to slope-intercept form. Show your work!

1 answer:

jeka57 [31]3 years ago

8 0

Point-slope equation=y+1=5(x+2)
slope intercept form=5x+9

You might be interested in

Hello I need help<br> Find the missing side lengths, leave your answers as radicals in simplest form

Jet001 [13]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$y = \frac{1}{2} \times \frac{8 \sqrt{3} }{3} \\$

$y = \frac{4 \sqrt{3} }{3} \\$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$x = \frac{ \sqrt{3} }{2} \times \frac{8 \sqrt{3} }{3} \\$

$x = \frac{8 \times { \sqrt{3} }^{2} }{2 \times 3} \\$

$x = \frac{8 \times 3}{2 \times 3} \\$

$x = \frac{8}{2} \\$

$x = 4$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

4 0

3 years ago

Suppose that rectangle ABCD is dilated to A'B'C'D' using the origin as the center and a magnitude of 2

Veronika [31]

Yo I’m just here so I can ask my question!
Answer explaining=

4 0

3 years ago

Read 2 more answers

Symplify by combining like terms:-17+2x+4x+5

k0ka [10]

6x-12
Combine 2x and 4x = 6x
Combine -17 and 5 = -12

6 0

3 years ago

Read 2 more answers

find an equation of the tangent line to the curve at the given point. y=sqrt(x) (1,1) Ive never been good with these equations a

Nady [450]

Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)= $\frac{1}{2 \sqrt{x} }$ (Derivation)
f´(x0)= $\frac{1}{2}$
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y = $\frac{1}{2}x+ \frac{1}{2}$

4 0

3 years ago

6. Determine if the two functions are inverses of one another.

-BARSIC- [3]

It will be yesssssssssssssssssssssssssssssssss

6 0

3 years ago