Y + 1 = -1/4(x - 5)
y + 1 = -1/4x + 5/4
y = -1/4x + 1/4
B. y = -1/4x + 1/4
![\frac{1}{2}(x+5)^2 + 9 = -15](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%28x%2B5%29%5E2%20%2B%209%20%3D%20-15%20)
![\frac{(x+5)^2+18}{2} = \frac{-30}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x%2B5%29%5E2%2B18%7D%7B2%7D%20%3D%20%20%5Cfrac%7B-30%7D%7B2%7D%20)
Cancel out the denominators.
(x+5)² + 18 = -30
(x+5)² = -30 - 18
(x+5)² = -48
The equation is impossible, we have a negative number.
There isn't a number that squared gives a negative number (the square is always positive).
√(x+5)² = +/- √-48
x+5 = +/- √-48
IMPOSSIBLE
You can write the result in imaginary numbers
x+5=+/- 4i√3
The order of operations helps keep answers for multi-step equations similar. If the proper order of operations are not followed, then answers may vary. To show an example:
4 / 2 - 1
The proper order of operations would be:
Divide first, before subtracting
4 / 2 - 1
2 - 1
1
But if subtracting was done before dividing:
4 / 2 - 1
4 / 1
4
So not following the proper order would yield different and erroneous answers.
Answer:
6/7 divided by 10/3= 18/70 or reduced 9/35
Step-by-step explanation:
6/7 divided by 10/3
6/7*3/10= 9/35
- What is supplementary angle ?
- When sum of two angles is 180°, then each of those two angles will be considered to be the supplementary angle of each other.Example : 150° and 30° are two angles, and their sum is 180°. So, 150° and 30° are supplementary angles.
____________________
<u>Explanation</u> :-
It's given an angle measures 168° more than the measure of its supplementary angle. We are asked to find measure of each angle!
- Let, one of the supplementary angle be "x" . Then the other angle becomes " (x + 168)° "
Sum of these two angles is equal to 180° . Since they are supplementary angles.
![\bf{\underline{\underline{\sf According\ to\ the\ question:-}}}](https://tex.z-dn.net/?f=%20%5Cbf%7B%5Cunderline%7B%5Cunderline%7B%5Csf%20According%5C%20to%5C%20the%5C%20question%3A-%7D%7D%7D%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf \twoheadrightarrow {x\ +\ x\ +\ 168^\circ\ =\ 180^\circ} }](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cbf%20%20%5Ctwoheadrightarrow%20%7Bx%5C%20%2B%5C%20x%5C%20%2B%5C%20168%5E%5Ccirc%5C%20%3D%5C%20180%5E%5Ccirc%7D%20%20%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow 2x + 168^\circ= 180^\circ](https://tex.z-dn.net/?f=%20%5Csf%20%20%5Ctwoheadrightarrow%202x%20%2B%20168%5E%5Ccirc%3D%20180%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow 2x = 180^\circ - 168^\circ](https://tex.z-dn.net/?f=%20%5Csf%20%20%5Ctwoheadrightarrow%202x%20%3D%20180%5E%5Ccirc%20-%20168%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow 2x = 12^\circ](https://tex.z-dn.net/?f=%20%5Csf%20%20%5Ctwoheadrightarrow%202x%20%3D%2012%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow x = \cancel{\dfrac{12^\circ}{2}}](https://tex.z-dn.net/?f=%20%5Csf%20%5Ctwoheadrightarrow%20x%20%3D%20%5Ccancel%7B%5Cdfrac%7B12%5E%5Ccirc%7D%7B2%7D%7D%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf \twoheadrightarrow x = 6^\circ }](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cbf%20%5Ctwoheadrightarrow%20x%20%3D%206%5E%5Ccirc%20%7D)
Then –
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \longrightarrow x +168^\circ](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5Clongrightarrow%20x%20%2B168%5E%5Ccirc)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\tt \longrightarrow 6^\circ+ 168^\circ](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clongrightarrow%20%20%206%5E%5Ccirc%2B%20168%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\tt \longrightarrow 174^\circ](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clongrightarrow%20174%5E%5Ccirc)
- The measures of the two given angles are 6° and 174°.
______________________