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igor_vitrenko [27]
3 years ago
9

Find the total area the regular pyramid. T.A. =

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer:

20 +4√2

Step-by-step explanation:

Find the total area the regular pyramid = A + 1/2ps

A is the Base area

p is the perimeter of the base

s is slant height

A = 1/2 * 4 * 4

A = 16/2

A = 8

p = 4 + 4 + (√4^2+4^2)

p = 8 + √32

p = 8 + 4√2

s = 4

Substitute

TSA = 8 + 8 + 4√2 + 4

TSA = 20 +4√2

Hence the total surface area is 20 +4√2

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Answer:

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Step-by-step explanation:

It is a result that a matrix A is orthogonally diagonalizable if and only if A is a symmetric matrix.  According with the data you provided the matrix should be

A=\left(\begin{array}{ccc}-9&-4&2\\ -4&-9&2\\2&2&-6\\\end{array}\right)

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With this in mind we can form the matrices P, D that diagonalizes the matrix A so.

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Now you only need to normalize each row of P dividing by its norm, as a row vector.

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