24w+6c=$23.40
5w+2c=$6.60
So you have to find c (chips) first. You have to make the number of chips in both equations cancel each other.
-3(5w+2c)=-3($6.60)
-15w-6c=$-19.80
Then subtract to get one formula
24w + 6c = $23.40
-15w - 6c = $-19.80
9w = $3.60
w=$.40
To check your answer, find how much one bag of chips costs:
5($.40) + 2c = $6.60
$2.00 + 2c = $6.60
2c = $4.60
c=$2.30
Plug your value for one water and one bag of chips into the formula:
5($.40) + 2($2.30)
$2.00 + $4.60
=$6.60
Then plug your values into the original problem:
24($.40) + 6($2.30)
$9.60 + $13.80
=$23.40
Answer:
y=
Step-by-step explanation:

multiply both sides
8y+5=6
move the constant to the right
8y=6-5
calculate
8y=1
divide both sides
y=
or y=0.125
Answer:
I think the answer is 5,000 .
Answer:
1) What is the probability a randomly selected bag will have a positive test = 0.132
2) what is the probability it actually contains a large amount of liquid = 0.3522
3) what is theprobability it does not contain a large amount of liquid = 0.6477
Step-by-step explanation:
The detailed explanation using the bayes rule is as shown in the attachment.
8%X + 7%(27000-X) = 2050
.08X + 1890 + .07X = 2050
.15X = 160
X = $1067.67