Adding the two equations
3x + 6y + 3x - 6y = 36+0
6x = 36
x = 6
.
subtracting second equation from first
(3x + 6y ) - (3x-6y) =36 -0
12y = 36
y = 3
.
therefore
x = 6 and y = 3
(6,3)
Answer:
Step-by-step explanation:
Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random
the probability
(a) The student is enrolled in mathematics=
(b) The student is enrolled in English.=
(c) The student is enrolled in both.=
(d) The student is enrolled in mathematics or English.=
(e) The student is enrolled in English but not in mathematics.
=
(f) The student is not enrolled in English or is enrolled in mathematics.
=
D. 55% of the time
45% of the time it will say positive
The other 55% of the time will come back negative.
Let

be the number of rides Chandler takes in a month. Then the cost with the MetroCard is still $81, but the cost without the MetroCard is

. So we can set up an equation representing what we want: "The cost with a MetroCard of r rides in a month is less than the cost without a MetroCard." In equations,

Thus, at a minimum, Chandler must take 41 rides for his MetroCard to be cheaper than not having it.
4 papers that are 2 inches by 2 1/2 inches