For this case, we have to:
By definition, we know:
The domain of ![f (x) = \sqrt [3] {x}](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%7D)
is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.
So, we have:
![y = \sqrt [3] {x-2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx-2%7D)
with
: ![y = \sqrt [3] {- 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B-%202%7D)
is defined.
![y = \sqrt [3] {x+2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%2B2%7D)
with ![x = 0:\ y = \sqrt [3] {2}](https://tex.z-dn.net/?f=x%20%3D%200%3A%5C%20y%20%3D%20%5Csqrt%20%5B3%5D%20%7B2%7D)
is also defined.
has a domain from 0 to ∞.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when.
While 
if it is defined for .
Answer:
Option b
4/5 is a fraction equivalent to 32/40. This is in simplest form.
Another fraction that is equivalent to 32/40 is 16/20.
Answer:
HERE IS YOUR ANSWER
Step-by-step explanation:
Use the mirror equation:
1/di + 1/do = 1/f
where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)
Substitute and solve for do.
1/do + 1/(-10 cm) = 1/(15 cm)
1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)
do = 6 cm
Hope it helps you
Regards,
Rachana
Answer
$37
Explanation
it costs $4.50 per sandwich so you multiply that by 6 which gets you $27. then you add the delivery fee ($10) to that and you get $37
hope this helps!!
Answer:
Ok so it's been a minute since I've done this however the answer would be A I think.
- 3x+2y=3
- subtract 3x and put it behind 2y
- divide by 2 throughout the entire equation
- subtract 1 3/2 on both sides of the equation
- you should get y=0
