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zloy xaker [14]
3 years ago
15

Find x thank you so much!

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

x

Step-by-step explanation:

You might be interested in
What does 45 - 4x equal
xxTIMURxx [149]
Let y = 0 to find the x-intercept(s).

0 = 45 − 4x

*Then subtract 45 from both sides*
-45 = -4x

*Next, DIVIDE both sides by -4*

-45
—— = x
-4

*NEXT, realize that TWO NEGATIVES MAKE A POSITIVE *

45. 4
——— = x {FLIP} x=——-
4. 45.


y-Intercept

Let x = 0 to find the y-intercept(s).


y = 45 −4(0)

NEXT, SIMPLIFY:

y=45
7 0
3 years ago
Please answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
Digiron [165]

Answer:

Okayy

Step-by-step explanation:

Since T is the centroid which is the center

Also T is a midpoint

Nt=tn=42

Hope this helps

8 0
3 years ago
The sign of the product of –35 and –625 is (positive, negative, zero)
ziro4ka [17]

Step-by-step explanation:

-35 x - 625 = 21875 so positive

263 x 0 = 0 so zero

-21 x 451 = - 9471 so negative

-350 x 89 = - 31150 so negative

3 0
3 years ago
Read 2 more answers
A construction company wants to hire carpenters for $220 a day and plumbers for $260 a day. The company wants to hire at least 1
joja [24]

Answer:


Step-by-step explanation:

Yes the company can hire 6 carpenters and 12 pumbers

So first lets find out how much it costs to have 6 carpenter for $220 a day.

$220 × 6 = $1320  this is how much it cost to pay 6 carpenters for one day.

Now lets find how much it cost to 12 plumbers at $260 a day.

$260 × 12 = $3120 this is how much it costs to pay 12 plumbers a day.

The total amount you have to pay to the workers is:

$3120 + $1320 = $4440

Your budget was $4500 so the total costs for the workers is $4440 which means you can hire those workers and you would still have $60.


3 0
3 years ago
given y>0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
jonny [76]
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx
\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx
\implies \dfrac12y^2=x^3+2x^2+C

When x=1 you have y=\sqrt{10}, so

\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2

and so the particular solution to the ODE is

\dfrac12y^2=x^3+2x^2+2

Then when x=0, you get

\dfrac12y^2=0^3+2(0)^2+2=2
\implies y^2=4
\implies y=2

where we omitted the negative root because it's given that y>0.
4 0
3 years ago
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