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Hunter-Best [27]
3 years ago
10

Select the correct answer.

Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0
I think it Is B.....
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The weights of cars passing over a bridge has a mean of 3550 lb and a standard deviation of 870 lb. Assume that the weights of t
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Step-by-step explanation:

Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs.  So choose appropriate answer accordingly (near the end)

Using the usual notations and formulas,

mean, mu = 3550

standard deviation, sigma = 870

Observed value, X = 3000

We calculate

Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839

Probability of weight below 3000 lbs

= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334

Answer:

Probability that a car randomly selected is less than 3000

= P(X<3000) = 0.2636 (to 4 decimals)

Probability that a car randomly selected is greater than 3000

= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)

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Question 3 of 10
Serjik [45]

Answer:

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Step-by-step explanation:

\frac{5(2x-3) -3(x+4)}{9} = \frac{10x-15-3x-12}{9} = \frac{7x-27}{9}

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Answer:

Option C. (-x,y)

Step-by-step explanation:

we know that

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