All categories

2 years ago

X

Mathematics

1 answer:

cricket20 [7]2 years ago

4 0

I think it’s the second option sorry if incorrect

You might be interested in

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height

Ilia_Sergeevich [38]

Answer:

$\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s$

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

$\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}$

From this point on, you have two possibilities, either you find each individual $y_{f}, y_{0}, t_{f}, t_{0}$ and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

$t_{f}-t_{0}=\Delta t$

and we also know that:

$t_{f}=t_{0}+\Delta t$

in order to find the final position, we can substitute this final time into the function, so we get:

$y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}$

so we can rewrite our formula as:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}$

$y_{0}$ will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

$y_{0}=29t-22t^{2}$

$y_{0}=29(1)-22(1)^{2}$

$y_{0}=7ft$

we can substitute it into our average velocity equation:

$\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}$

and we also know that the initil time will always be 1, so we can substitute it as well.

$\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}$

so we can now simplify our formula by expanding the numerator:

$\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}$

$\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}$

we can now simplify this to:

$\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}$

Now we can factor Δt to get:

$\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}$

and simplify

$\overline{v}=-15-22\Delta t$

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

$\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s$

$\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s$

$\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s$

$\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s$

5 0

2 years ago

Mr. Quillin showed students part of the prime factorization of 90. One factor is

kaheart [24]

24.....................

4 0

2 years ago

The owner of a lemonade stand that costs 2 dollars per gallon with juice that costs 7 dollars per gallon. He gets 20 gallons of

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

Your answer

62.222 gallons

Mark it as Brainlist answer. Follow me.

7 0

2 years ago

How is the following written with only one exponent?<br>a^3 . a^5

Sonbull [250]

Answer:

The expression 103 is called the exponential expression. ... The exponent applies only to the number that it is next to. ... If −3 is to be the base, it must be written as (−3)4, which means −3 • −3 • −3 ... From row 1 to row 2, the exponential form goes from 105 to 104. ... Following the pattern, you see that 100 is equal to 1.

Step-by-step explanation:

6 0

2 years ago

Determine the x-intercept and the y-intercept for the graph of this equation:<br> 2x - 3y + 36 = 0

natali 33 [55]

QUESTION:- DETERMINE THE X-INTERCEPT AND THE Y-INTERCEPT FOR THE GRAPH OF THE EQUATION.

EQUATION:- 2x - 3y + 36 = 0

STANDARD EQUATION:- y=mx+c

where

m-> slope.
c-> Y-INTERCEPT
x&y are the coordinates.

SO GIVEN EQUATION:- 2x - 3y + 36 = 0

WE CAN SOLVE THIS TO CHANGE IN FORMAT OF STANDARD EQUATION

$2x - 3y + 36 = 0 \\ 2x + 36 =3y \\ y = \frac{2}{3} x + \frac{36}{3} \\ y = \frac{2}{3} x + \frac{ \cancel{36}^{ \: \: 12} }{ \cancel3} \\ y = \frac{2}{3} x + 12 \\$

SO :-

$m = \frac{2}{3} \\ y - intercept = 12 \: ans$

$slope = \frac{y2 - y1}{x2 - x1} \\ \frac{2}{3} = \frac{0 - 12}{x - 0} \\ 2x = ( - 12) \times 3 \\ x = \frac{ - \cancel{12}^{ \: \: 6} \times 3 }{ \cancel{2}} \\ x = - 18 \: \: ans$

7 0

2 years ago