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Irina18 [472]
3 years ago
12

What is the distance between the points (1, 25) and (4, 21)

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Hello!

To find the distance between the points (1, 25) and (4, 21), you need to use the distance formula.

The distance formula is: d =\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}. With the distance formula, you have to assign the ordered pairs before substituting them into the formula, which is also used to to find the slope of functions.

d =\sqrt{(21-25)^{2}+(4-1)^{2}}

d =\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

d=5

Therefore, the distance between the two points is 5 units.

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If \frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}, the value of a and b is given as a = 34 and b = 0

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2 years ago
2x + y = 12<br> 4x - 3y = 2
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Answer:

The value of x for equation is 3.4

The value of y for equation is 5.2  

Step-by-step explanation:

Given as :

The two linear equation are

2 x + y = 12           ........A

4 x - 3 y = 2              .........B

Now, Solving both equations , we get

3 × ( 2 x + y ) + (4 x - 3 y) = 3 × 12 - 2

Or, 6 x + 3 y + 4 x - 3 y = 36 - 2

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Or, 10 x + 0 = 34

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Or, y = 12 - 2 × 3.4

Or, y = 12 - 6.8

∴ y = 5.2

So, The value of y for equation , y = 5.2

Hence, The value of x for equation is 3.4  and The value of y for equation is  5.2   Answer

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