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Oksi-84 [34.3K]
3 years ago
14

A survey of 125 randomly selected teens ages 13 to 16 found that 33 of them play soccer, 27 of them play basketball, 24 of them

play baseball, 28 of them play softball, 16 of them play a sport not listed, and 35 of them did not play a sport at all. Which inference can best be made about the results of the survey? Many teens ages 13 to 16 play more than one sport. Most teens ages 13 to 16 don't play a sport. Many teens ages 13 to 16 prefer to play football. More teens play soccer than any other sport.
Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0
I think it is "More teens play soccer than any other sport"
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What percent of 1600 is 2?
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Based on a random sample of 25 units of product X, the average weight is 102 lb and the sample standard deviation is 10 lb. We w
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Answer:

t=\frac{102-100}{\frac{10}{\sqrt{25}}}=1      

t_{crit}= 2.49

Since the calculated value is lower than the critical value we have enough evidence to FAIL to reject the null hypothesis

So then we can conclude that the population mean is not significantly higher than 100

Step-by-step explanation:

Data given and notation      

\bar X=102 represent the mean score for the sample  

s=10 represent the standard deviation for the sample      

n=25 sample size      

\mu_o =100 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is higher than 100, the system of hypothesis would be:    

Null hypothesis:\mu \leq 100      

Alternative hypothesis:\mu > 100      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

     

Calculate the critical value

We need to find the degrees of freedom first, given by:

df= n-1= 25-1 = 24

Since we are conducting a right tailed test we need to find a critical value on the t distribution with 24 degrees of freedom that accumulates 0.01 of the area on the right and we got:

t_{crit}= 2.49

Since the calculated value is lower than the critical value w have enough evidence to FAIL to reject the null hypothesis

So then we can conclude that the population mean is not significantly higher than 100

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