Answer:
We have a1 = 27 and r = 3 (because 27:9 = 3; 9:3 = 3; 3:3 = 1);
Then s = 27 / (1 - 3) ;
Finally, s = - 27 / 2;
Step-by-step explanation:
How far did the frog jump? the answer is one of the solutions of the quadratic equation

because that's where the frogs height is 0 (y=0) feet.
Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.
The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825
So, the correct answer is (a) 30 ft far and 3.83 high.
The answer is 153.86:

if we round the answer it will be
153.9
Answer:
break it in three rectangles!
let the rectangles be A B and C
For A = 4×2
For B 3× (4-2)
For C = 4×3
Total area 26cm²
Answer: D, hope that helps!