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2 years ago

The slope of a line is 1, and the y-intercept is -1. What is the equation of the line written in slope-intercept form?

Mathematics

1 answer:

Nat2105 [25]2 years ago

8 0

Answer:

y=x-1

Step-by-step explanation:

since the slope is just one up and one over and it's positive it would just be x

and since the intercept is just -1 it would be y=x-1

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Vitek1552 [10]

It is exponential growth because it says 18.36% "more than" and it can be linear because it does not stay at a constant rate of change. Answer: Exponential growth
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4 0

2 years ago

The sides of a triangle are in the ratio 3 : 4 : 5. What is the length of each side if the perimeter of the triangle is 90 cm

svet-max [94.6K]

The sides of the triangle are 3x, 4x and 5x

3x + 4x + 5x = 90
12x = 90
x = 90/12
x = 7.5

first side = 3x = 3 * 7.5 = 22.5 cm
second side = 4x = 4 * 7.5 = 30 cm
third side = 5x = 5*7.5 = 37.5 cm

7 0

3 years ago

How should I solve for x and what is x?

algol [13]

Answer:

x =12

Step-by-step explanation:

We can use the Pythagorean theorem to solve for x

a^2 + b^2 = c^2

16^2 + x^2 = 20^2

256 +x^2 = 400

Subtract 256 from each side

256-256 +x^2 = 400-256

x^2 =144

Take the square root of each side

sqrt(x^2) =sqrt(144)

x = 12

8 0

3 years ago

What is the value of x? 42 45 3 15

mylen [45]

Answer:

125 is the value of the question

3 0

3 years ago

Find equations of the spheres with center(1, −1, 6)that touch the following planes.a) xy-planeb) yz-planec) xz-plane

Misha Larkins [42]

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

$(x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36$

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

$(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1$

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

$(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1$

Hence , this is the required solution .

4 0

3 years ago