Answer:
a)
AB is on the latitude 30°N.
<u>Find AB:</u>
- AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km
BC is along longitude 35°W
<u>Find BC:</u>
- BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km
<u>Total distance traveled:</u>
- 6482.15 + 5585.77 = 12067.92 km
<u>Convert the distance to nautical miles:</u>
12067.92/1.86 = 6488.13 nautical miles
b)
<u>Find the average speed:</u>
- 6488.13/22 = 294.92 nautical miles / hour
<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>
Following the principle of supplements angles, the angle next to the 101 is 79°. 79+38+c(call the third angle c) = 180
c = 180-117 =63° x is supplemental to c so 180 = x +c
180=x + 63
x =117
Step-by-step explanation:
S = { 1, 2, 3, 4, 5, 6 7, 8 }
n ( S ) = 8
Let A be the event of getting 4,
A = { 4 }
n ( A ) = 1
P ( A )
= n ( A ) / n ( S )
= 1 / 8
Therefore, the probability of spinning a 4 is 1 / 8.
S = { A, B, A, C, A, B }
n ( S ) = 6
Let Y be the event of getting C,
Y = { C }
n ( Y ) = 1
P ( Y )
= n ( Y ) / n ( S )
= 1 / 6
Therefore, the probability of spinning a C is 1 / 6.
Answer:
ur correct u got it.
Step-by-step explanation:
