Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
First you add all given angles up to equal 180 to give you Times in to equations
A= 125 degrees
C= 35 degrees
I hope I help you and good luck
Answer:
x=6
Step-by-step explanation:
10-5x=3(x-4)-2(x+7)
Distribute
10-5x=3x-12-2x14
Combine like terms
10-5x = x-26
add 5x to each side
10-5x+5x = x+5x-26
10 = 6x-26
Add 26 to each side
10+26 = 6x-26+26
36 = 6x
Divide by 6
36/6 = 6x/6
6 =x
Like what u need help with
1,068 is your answer. There will be 356 in each shipment because 1,424 divided by 4 is 356. And 356 times 3 is 1,068.
