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densk [106]
3 years ago
14

The diagram shows 3 identical circles inside a rectangle.

Mathematics
1 answer:
Ilya [14]3 years ago
5 0

Answer:

11700 mm²

Step-by-step explanation:

A rectangle is a quadrilateral with two equal, opposite and parallel sides. Each of the angles in a rectangle is 90°.

The horizontal distance of the rectangle = r + r + r + r = 4r

The vertical distance = r + h + r = 2r + h

Where h is the distance between the midpoint of the 2 up circles and the midpoint of the down circle.

Using Pythagoras:

 (2r)² = h² + r²

h² + r² = 4r²

h² = 3r²

h = √3r²

h = r√3

Vertical distance = 2r + h = 2r + r√3

Area of rectangle = vertical distance * horizontal distance

Area = 4r * (2r + r√3) = 8r² + 4r²√3 = 4r²(2 + √3)

Substituting:

Area = 4r²(2 + √3) = 4(28²)(2 + √3) = 11703.711 mm²

Area = 11700 mm² to 3 s.f

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        \large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}

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We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

                            \large\displaystyle\text{$\begin{gathered}\sf L  = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4  }{x^{3}-5  }  \end{gathered}$}\\

                                \ \  = \lim_{x \to \infty\frac{\frac{x^{4}  }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} }    }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}}   }  }

                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

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2 years ago
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