Answer;
They are 3 terms
The terms are the numbers and the variables separated by the minus sign and the plus sign
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
A. {16}
Step-by-step explanation:
1/4 = x^-1/2
We have the exponent rule a^-1 = 1/a^1
Applying the rule, we get
1/4 = 1/x^1/2
x^1/2 = √x
1/4 = 1/√x
Now let's cross multiplying, we get
√x = 4
Taking square on both sides, we get
x = 16
The answer: A. {16}
Hope this will helpful.
Thank you.
Divide the perimeter by 3 to get 8 then use the equation for the area of a triangle (a= BH1/2) and your answer is 32
