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ivann1987 [24]
1 year ago
10

Given the quadriatic equation

Mathematics
1 answer:
vazorg [7]1 year ago
8 0

Answer:

⇒  The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0

∴  We get, a=1b=−k,c=9

⇒  It is given that roots are real and distinct.

∴  b2−4ac>0

⇒  (−k)2−4(1)(9)>0

⇒  k2−36>0

⇒  k2>36

⇒  k>6 or k<−6

∴  We can see values of k given in question are correct.

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Answer:

Point (0,0)

Step-by-step explanation:

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We will check which of the given options will be applied for the inequality

A) (1,0)

Substitute with x = 1 and y = 0

0 > 12*1 - 11

0 > 1   ⇒ Wrong

So, Point (1,0) is not part of the solution of the inequality.

B) (3,2)

Substitute with x = 3 and y = 2

2 > 12*3 - 11

0 > 25  ⇒ Wrong

So, Point (3,2) is not part of the solution of the inequality.

C) (1,1)

Substitute with x = 1 and y = 1

1 > 12*1 - 11

1 > 1   ⇒ Wrong

So, Point (1,1) is not part of the solution of the inequality.

D) (0,0)

Substitute with x = 1 and y = 0

0 > 12*0 - 11

0 > -11  ⇒ True

So, Point (0,0) is part of the solution of the inequality.

Also, see the attached figure which represents the given inequality

The shaded area represents the solution of the inequality, and we can note that point (0,0) is part of the solution of the inequality

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3 years ago
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