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ivann1987 [24]
2 years ago
10

Given the quadriatic equation

Mathematics
1 answer:
vazorg [7]2 years ago
8 0

Answer:

⇒  The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0

∴  We get, a=1b=−k,c=9

⇒  It is given that roots are real and distinct.

∴  b2−4ac>0

⇒  (−k)2−4(1)(9)>0

⇒  k2−36>0

⇒  k2>36

⇒  k>6 or k<−6

∴  We can see values of k given in question are correct.

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Answer:

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Step-by-step explanation:

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3 (\frac{3}{5} )=\frac{15+3}{5}=\frac{18}{5}

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3 years ago
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There are two ways to find or determine for the value of c. In the first method, we can use addition and subtraction to isolate the variable c from the other variables. In the second method, we can use the transposition of variables to isolate the variable c from the other variables.

So solving for the value of c:

 

<span>Using 1st method: Addition and Subtraction</span>

We are given:

240 = 6 z + c

Simply subtract 6 z on both sides:

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Cancelling 6 z – 6 z on the right side:

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<span>Using the 2nd method: Transposition</span>

240 = 6 z + c

What we are going to do here is to simply transpose the variable 6 z from the right side to the left side of the equation so that we are left with c alone on the right side. Always remember that when we transpose, the symbol becomes opposite. That is:

240 + (- 6 z) = c

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or

<span>c = 240 – 6 z</span>

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