Question

Given the quadriatic equation

Answer 1

Answer:

⇒  The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0

∴  We get, a=1b=−k,c=9

⇒  It is given that roots are real and distinct.

∴  b2−4ac>0

⇒  (−k)2−4(1)(9)>0

⇒  k2−36>0

⇒  k2>36

⇒  k>6 or k<−6

∴  We can see values of k given in question are correct.