Answer:
Explanation:
1. The processes of diffusion in diagram A and B is that one side of the membrane is hypertonic. The other side is hypotonic. Based on this, Diagram A shows that the one space has no solute particles causing the particles to move against gradiation. The movement is shown in Diagram B. This process is used to equalize the solute particles in the solution.
2. In the diagram C, we can see that enough particals have moved over to the other side, or against the concentration gradient. The solution is now isotonic or equilibrium.
Answer:
b
Explanation:
some are the same while others are different (traits)
The diploid is 30. The haploid is 15. Option C is most likely correct.
