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2 years ago

Plsssss help 30 POINTS

Mathematics

2 answers:

Olegator [25]2 years ago

7 0

2(7)+2(2)=18

just adding all sides

Finger [1]2 years ago

4 0

Answer:

perimeter is the outside, 7+7+2+2= 18

Step-by-step explanation:

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Please find the answers below

spayn [35]

Answer:

option 3 is the correct.....

Step-by-step explanation:

multiplying all the algebraic expressions

volume of cuboid = 3x (x+3)(x+1)

= 3x³ + 12x² + 9x

3 0

2 years ago

(question 31) if arc mBC =120 and arc mAD =50 whatis the measure of angle DYC

g100num [7]

<h3>Answer: D) 95</h3>

===============================================================

Explanation:

First, let's calculate angle BYC. This is the angle formed by the chords that subtend the arcs mentioned. This angle faces or is aimed toward the direction of the arcs. To find this angle, we'll average the arc measures like so:

angle BYC = (arcAD + arcBC)/2

angle BYC = (50+120)/2

angle BYC = 170/2

angle BYC = 85 degrees

Then we'll use the idea that angles BYC and DYC are supplementary (aka they form a straight 180 degree angle)

angleBYC + angleDYC = 180

angleDYC = 180 - angleBYC

angleDYC = 180 - 85

angleDYC = 95 degrees

which is why the answer is choice D.

5 0

2 years ago

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$