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masya89 [10]
3 years ago
14

Scott earned 20 points more on his most recent math test than he earned on the previous test. If he earned at least 80 points on

the most recent math test, how many points did he earn on the previous test?
Question 16 options:

s ≤ 60


s 60


s ≥ 60
Mathematics
1 answer:
NARA [144]3 years ago
7 0

9514 1404 393

Answer:

  s ≥ 60

Step-by-step explanation:

If Scott earned 20 points more on this test, then he earned 20 points less on the last test. 20 points less than "at least 80" is "at least 60."

  s ≥ 60

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HELPP!! Whats -8/9 divided by 2/3
galina1969 [7]

Answer:

-4/3

Step-by-step explanation:

You can also use mathpapa it's a calculator that gives you the answer and solves it for you step by step.

please mark me brainliest :)

5 0
2 years ago
If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.
solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

WX=\sqrt{(-3-(-10))^2+(-1-4)^2}

WX=\sqrt{(-3+10)^2+(-5)^2}

WX=\sqrt{(7)^2+(-5)^2}

WX=\sqrt49+25}

WX=\sqrt{74}

Similarly,

XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}

WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}

Now,

WX=WY

So, triangle is an isosceles triangles.

and,

WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2

WX^2+WY^2=74+74

WX^2+WY^2=148

WX^2+WY^2=(2\sqrt{37})^2

WX^2+WY^2=WY^2

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0
3 years ago
The profit function for the first version of the device was very similar to the profit function for the new version. As a matter
NeTakaya

Answer:

a) - Compressing the P(new) function by a scale of 0.5 about the y axis.

- Moving the P(new) function down by 104 units.

b) The two simplified functions for P(original)

-0.08x² + 10.8x – 200.

-0.16x² + 21.6x – 504.

Step-by-step explanation:

Complete Question

An electronics manufacturer recently created a new version of a popular device. It also created this function to represent the profit, P(x), in tens of thousands of dollars, that the company will earn based on manufacturing x thousand devices: P(x) = -0.16x² + 21.6x – 400.

a. The profit function for the first version of the device was very similar to the profit function for the new version. As a matter of fact, the profit function for the first version is a transformation of the profit function for the new version. For the value x = 40, the original profit function is half the size of the new profit function. Write two function transformations in terms of P(x) that could represent the original profit function.

b. Write the two possible functions from part a in simplified form.

Solution

The equation for the new profit function is

P(x) = -0.16x² + 21.6x – 400

At x = 40, the original profit function is half the size of the new profit function

First, we find the value of the new profit function at x = 40

P(x) = -0.16(40)² + 21.6(40) – 400 = 208

Half of 208 = 0.5 × 208 = 104

P(original at x = 40) = P(new at x = 40) ÷ 2

Since we are told that P(original) is a simple transformation of the P(new)

P(original) = P(new)/2 = (-0.16x² + 21.6x – 400)/2 = -0.08x² + 10.8x – 200 ... (eqn 1)

Or, P(original) = 104

-0.16x² + 21.6x – 400 = 104

P(original) = -0.16x² + 21.6x – 400 - 104 = -0.16x² + 21.6x – 504.

So, the two functions that are simple transformations of P(new) to get P(original) are

-0.08x² + 10.8x – 200

Obtained by compressing the P(new) function by a scale of 0.5 about the y axis.

And

-0.16x² + 21.6x – 504.

Obtained by moving the P(new) function down by 104 units.

Hope this Helps!!!

4 0
3 years ago
Help!! Thank you so much!!
Orlov [11]

The volume we're looking for is the volume of both cones in the figure.

The volume of a cone is  V=\pi r^2\frac{h}{3} .

So, V_{tot} = V_{1} + V_2 .

<u>Cone 1's variables:</u>

r = 2.6

h = 5

<u>Cone 2's variables:</u>

r = 2.6

h = 3

Now we can just plug and chug!

V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68

V = c. 56.6 cubic units

5 0
3 years ago
(-3y2 + 2y + 9) (7y - 2)​
Dennis_Churaev [7]

Answer:

simplified is -22y^3+20y^2+59y-18

Step-by-step explanation:

8 0
3 years ago
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