Answer:
Look below
Step-by-step explanation:
The mean of the sampling distribution always equals the mean of the population.
μxˉ=μ
The standard deviation of the sampling distribution is σ/√n, where n is the sample size
σxˉ=σ/n
When a variable in a population is normally distributed, the sampling distribution of for all possible samples of size n is also normally distributed.
If the population is N ( µ, σ) then the sample means distribution is N ( µ, σ/ √ n).
Central Limit Theorem: When randomly sampling from any population with mean µ and standard deviation σ, when n is large enough, the sampling distribution of is approximately normal: ~ N ( µ, σ/ √ n ).
How large a sample size?
It depends on the population distribution. More observations are required if the population distribution is far from normal.
A sample size of 25 is generally enough to obtain a normal sampling distribution from a strong skewness or even mild outliers.
A sample size of 40 will typically be good enough to overcome extreme skewness and outliers.
In many cases, n = 25 isn’t a huge sample. Thus, even for strange population distributions we can assume a normal sampling distribution of the mean and work with it to solve problems.
8.5 / 0.45 = 18.89.....and since u cant have 0.89 of a pea, ur answer would be 18 peas.
Answer:
The equation means x times 4 x 8.
Step-by-step explanation:
a dot means multiplication and in PEMDAS things in parenthesis should be done first so that is the simplified version of the equation.
The degree of a polynomial is the highest exponent or sum of exponents of the variables in the individual terms of a polynomial.
Looking at each the polynomial:
3x5 + 8x4y2 – 9x3y3 – 6y5: Degree is 6 (look at the 2nd and 3rd term)
2xy4 + 4x2y3 – 6x3y2 – 7x4: Degree is 5 (look at 1st, 2nd, and 3rd term)
8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4: Degree is 6 (look at 1st term)
–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5: Degree is 6 (look at 1st and last term)
Therefore, the answer is the second option:
2xy4 + 4x2y3 – 6x3y2 – 7x4
