Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
usub from where
Step-by-step explanation:
To find the mid point add both X coordinates together and divide by 2 and then do the same with the y coordinates.
X coordinate: 4 + -6 = 4-6 = -2 / 2 = -1
Y coordinate: -2 + 3 = 1 / 2 = 1/2
Midpoint: ( -1, 1/2)
Answer:
Step-by-step explanation:
Solution:
Given dimensions of the rectangular sheet
Length = 28 cm
Breadth =22 cm
If the sheet is rolled to form a cylinder then the length becomes height and breadth becomes circumference of the base of a cylinder.
So Height of the cylinder (h)= 28 cm
Circumference of the base of a cylinder
Xavier
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good luck :)
