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3 years ago

6x(x^2-x+7) Simplify your answer

Mathematics

2 answers:

Slav-nsk [51]3 years ago

7 0

Answer:

Step-by-step explanation:

6x(x²-x+7) = 6x³-6x²+42x

Tcecarenko [31]3 years ago

4 0

Answer:

6x^3-6x^2+42x

Step-by-step explanation: hoped i helped

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A population of bears decreases exponentially.

timurjin [86]

Answer:

0.8

Step-by-step explanation:

The annual factor will be found by dividing any year's population by the population of the year before. The points most easily read from the graph are the populations for years 0 and 1. Then the annual factor is ...

factor = (year 1 population)/(year 0 population) = 320/400

factor = 0.8

4 0

2 years ago

There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the

algol13

The probability is 3/14. There are 2 multiples of 4 in 14, which is 8 and 12. There is only 1 multiple of 6 in 14 which is 12. 1+2=3. It is possible outcomes over total outcomes so 3/14.

6 0

3 years ago

Read 2 more answers

Find the LCM (Least Common Factor) of 12 and 27 using prime factorizations

Aneli [31]

The LCM (least common factor) of 12 and 27 is the number: 3

5 0

3 years ago

PLEASE HELP

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

I don’t know how to do this. Can you help please help me ?

N76 [4]

Answer:

sin = -√3/2
cos = -1/2
tan = √3
sec = -2
csc = (-2/3)√3
cot = (√3)/3

Step-by-step explanation:

See the attached picture for a drawing of the angle and its terminal point coordinates. Those are (cos(4π/3), sin(4π/3)), so we have the following trig function values:

sin(4π/3) = -√3/2

cos(4π/3) = -1/2

tan(4π/3) = sin/cos = √3

sec(4π/3) = 1/cos = -2

csc(4π/3) = 1/sin = -(2√3)/3

cot(4π/3) = 1/tan = (√3)/3

_____

<em>Additional comment</em>

It helps to know that 1/√a = (√a)/a. This lets you write the ratios with a rational denominator in each case.

3 0

3 years ago