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gladu [14]
2 years ago
10

Given f(x) = -2x+6 find the following: will mark as branliest

Mathematics
2 answers:
wlad13 [49]2 years ago
5 0

Answer:

im pretty sure the answer is -12

Step-by-step explanation:

0=-2x+6

-6=-2x

x=3

-4×3=-12

tamaranim1 [39]2 years ago
5 0
<h2>Answer: −4f  Step-by-step explanation: Simplify the expression. </h2>
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Somebody help me please
Sauron [17]

Answer:

Here is the answer with the steps

Step-by-step explanation:

Hope you liked it!!

3 0
3 years ago
Could someone pls explain this step by step? Really simplify it pls because I don't understand it at all.
Lunna [17]

Answer:

  • y = 2x -6
  • y = -x +2
  • y = 4/5x -2
  • y = -3/2x +4

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx +b . . . . . where m is the slope, and b is the y-intercept

For these equations, writing them in slope-intercept form means "solve for y." You always do any "solve for ..." problem by undoing the operations that are done to the variable. Addition is undone by adding the opposite. Multiplication is undone by division.

As always, whatever operation we perform on one side of the equal sign must also be performed on the other side. That is how the equal sign remains valid.

__

<h3>a)</h3>

  1/2y = x -3

All we need to do is get rid of the coefficient of y. We can do that by dividing by 1/2, or multiplying by 2. The latter is easier to see, perhaps.

 2(1/2y) = 2(x -3)

  y = 2x +2(-3)

  y = 2x -6

__

<h3>b)</h3>

  x +y = 2

Here, we need to undo the addition of x. We do that by adding (-x) to both sides of the equation.

  -x +x +y = -x +2

  y = -x +2

__

<h3>c)</h3>

  4x -5y -10 = 0

This is a combination of the above operations. We can separate the y-term from the others by either subtracting the others, or adding the opposite of the y-term. We choose the latter, because that will give a positive coefficient for y. Adding 5y to both sides gives ...

  4x -5y +5y -10 = 5y

  5y = 4x -10 . . . . . . . . simplify and put y on the left

Now, we need to divide by the coefficient of y. We do that to both sides of the equation.

  5y/5 = (4x -10)/5

  y = 4/5x -10/5

  y = 4/5x -2

__

<h3>d)</h3>

  3x = -2y +8

We have a constant with the y-term. To get rid of it, we add its opposite to both sides.

  3x -8 = -2y +8 -8

  3x -8 = -2y

As before, we divide by the coefficient of y:

  (3x -8)/(-2) = (-2y)/(-2)

  -3/2x +4 = y

  y = -3/2x +4

3 0
2 years ago
A regular hexagon has an area of 750.8 cm. The side length is 17 cm. Find the apothem.
kompoz [17]

Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.

We have to find the apothem of the regular hexagon.

The formula for determining the apothem of regular hexagon is s \div {{2 \tan (\frac{180}{n})}, where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.

So, apothem = 17 \div {2 tan(\frac{180}{6})

= 17 \div {2 tan(30)

= 17 \div {1.15}

= 14.78 units

Therefore, the measure of apothem of the regular hexagon is 14.7 units.

Option B is the correct answer.

5 0
3 years ago
Help me with this one
Artist 52 [7]

9514 1404 393

Answer:

  "complete the square" to put in vertex form

Step-by-step explanation:

It may be helpful to consider the square of a binomial:

  (x +a)² = x² +2ax +a²

The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...

  2a = 1

  a = 1/2

That means we can write ...

  (x +1/2)² = x² +x +1/4

But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:

  x^2+x+1\\\\=(x^2+x+\frac{1}{4})+\frac{3}{4}\\\\=(x+\frac{1}{2})^2+\frac{3}{4}

_____

Another way to consider this is ...

  x² +bx +c

  = x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*

  = (x +b/2)² +(c -(b/2)²)

for b=1, c=1, this becomes ...

  x² +x +1 = (x +1/2)² +(1 -(1/2)²)

  = (x +1/2)² +3/4

_____

* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).

5 0
3 years ago
For what value of k will these pairs of simultaneous equations have no solution?
yKpoI14uk [10]
Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=\frac{k+3}{k-12}
Also y=\frac{5k}{k-12}
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.
4 0
3 years ago
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