To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
The answer would be (0,5)
Answer:
x=3.4
y=-6.75
Step-by-step explanation:
5x+4y=-10 (equation 1 )
-5x+3y=-17 (equation 2)
7y=-27
y=-6.75
substitution (equation 1 ) y=-6.75
5x-27=-10
5x=17
x=3.4
Answer:
I do not know
Step-by-step explanation:
Answer:
p=2
Step-by-step explanation:
4.05p+14.40=4.50(p+3) < equation
4.05p+14.40=4.50p+13.50 < multiply
14.40=.45p+13.50 < subtract
.9=.45p < subtract
2=p < divide
