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3 years ago

Solve for x round to the newest 10th i’d necessary

Mathematics

1 answer:

docker41 [41]3 years ago

5 0

Answer:

x = 43.7°

Step-by-step explanation:

Reference angle (θ) = x°

Opposite side length = 43

Adjacent side length = 45

Apply the trigonometric function, TOA, which is:

Tan θ = Opp/Adj

Substitute

$Tan(x) = \frac{43}{45}$

$x = Tan^{-1}(\frac{43}{45})$

x = 43.7° (nearesth tenth)

You might be interested in

Triangle ABC is an isosceles triangle in which side

Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using this formula, we get

$AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5$

$BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}$

$AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5$

Now,

Perimeter of triangle ABC = AB + BC + AC

$=5+\sqrt{10}+5$

$=10+\sqrt{10}$

So, perimeter of triangle ABC is $10+\sqrt{10}$ units.

Therefore, the correct option is B.

4 0

3 years ago

Read 2 more answers

Solve the equation. StartFraction dx Over dt EndFraction equals StartFraction 1 Over x e Superscript t plus 7 x EndFraction An i

MAVERICK [17]

Answer:

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

Step-by-step explanation:

We are given that

$\frac{dx}{dt}=\frac{1}{xe^{t+7x}}$

We have to find the implicit function

Using separation variable method

$\frac{dx}{dt}=\frac{1}{xe^t\cdot e^{7x}}$

By using property $x^a\cdot x^y=x^{a+y}$

$xe^{7x}dx=e^{-t}dt$

By using property $\frac{1}{x^a}=x^{-a}$

Taking integration on both sides

$\int xe^{7x}dx=\int e^{-t}dt$

Parts integration method

$\int u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

By parts integration method

$x\int e^{7x}dx-\int (\frac{dx}{dx}\int e^{7x}dx)dx=-e^{-t}+C$

Using formula $\int e^{ax} dx=\frac{e^{ax}}{a}+C$

$\frac{xe^{7x}}{7}-\frac{1}{7}\int e^{7x}dx=-e^{-t}+C$

$\frac{xe^{7x}}{7}-\frac{1}{49}e^{7x}+e^{-t}=C$

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

We are given that

$F(x,t)=C$

$F(x,t)=\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

8 0

3 years ago

MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD

Varvara68 [4.7K]

Answer:

$\sf \: Proved \: \angle \: OAD \: = \angle \: OCD$

Step-by-step explanation:

Given:

Mn is diameter of circle having centre O

and BD = OD,

To prove that:

 $\angle \: OAD \: = \angle \: OCD$ 

Solution:

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

$\angle \: OBD \: = \angle \: OCD$

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

$\angle \: OBD \: = \angle \: OAB \\ \angle \: OAB \: = \angle \: OAD (same \: angles) \\ \angle \: OBD \: = \angle \: OAD$

Consider above prove as statement B

From Statement A & B we can say that

$\angle \: OAD \: = \angle \: OCD$

Thanks for joining brainly community!

5 0

2 years ago

For a scavenger hunt, Jim's mom distributed a bag of 440 jelly beans evenly into 20 plastic containers and hid them around the y

natulia [17]

Answer: 11

Step-by-step explanation:

Given

Jim's mom distributed a bag of 440 Jelly beans evenly in to 20 Plastic bags

i.e.each bag has $\frac{440}{20}=22$ Jelly.

After the hunt, Jim has 242 Jelly. This much Jelly constitutes

$\Rightarrow \dfrac{242}{22}=11\ \text{bags}$

Therefore, Jim has 11 bags of Jellys

6 0

3 years ago

Dimensions of Box 2:x by 4x-1 by x^3 The volume of Box 2 is given by

PIT_PIT [208]

Answer:

4x^5 – x^4

Step-by-step explanation:

i took it and was correct

6 0

2 years ago