The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)
The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)
Answer: The system of inequalities would produce the region indicated on the graph is Option B
Answer:
hey can you help me with this? it's my deadline today
The answer is <span>B.154/d = 44/14
</span>
<span>In a circle, the circumference (C) and diameter (D) vary directly:
C = kD
k = C/D
Circle 1: k = C1/D1
Circle 2: k = C2/D2</span>
C1/D1 = C2/D2
C1 = 154
D1 = ?
C2 = 44
D2 = 14
154/D1 = 44/14
So, the choice B. is correct.
Answer:
y = 3x + 4
Step-by-step explanation:
✔️First, find the slope using any two given pairs form the table, say (2, 10) and (5, 19):
Slope (m) = ∆y/∆x = (19 - 10) / (5 - 2) = 9/3
m = 3
✔️Find y-intercept (b) by substituting (x, y) = (2, 10) and m = 3 into y = mx + b
10 = 3(2) + b
10 = 6 + b
10 - 6 = b
4 = b
b = 4
✔️Write the equation by substituing m = 3 and b = 4 into y = mx + b
y = 3x + 4
