Find two consecutive odd integers whose sum is 84.

kherson [118]

Answer in fraction form is exactly 2/27
Answer in decimal form is approximately 0.07407

========================================================

Explanation:

4 people play both,9 play flat flute only, 12 play piano only.
So 4+9+12 = 13+12 = 25 people play one instrument only or they play both.

We have 27 people total meaning that 27-25 = 2 play neither instrument.

Divide the values 2 and 27 to get
2/27 = 0.07407
this value is approximate (rounded to five decimal places)

5 0

2 years ago

Estimate the MAXIMUM number of people that can be in your park at one time, before it’s too crowded. Use this information for yo

Serga [27]

75,000 divided by 150, is 500, meaning they allow 500 people per acre. 500 times 145 is 72,500, meaning the capacity for a park your size should be 72,500 people.

3 0

2 years ago

One page of a petition can hold p signatures. You were able to get 4p+5 people to sign the petition. Your friend was able to get

leva [86]

Answer:

6p - 2

Step-by-step explanation:

The expression that needs to be made in this question refers to the total number of people that signed the petition. To calculate this we need to add the total number of signatures that both you and your friend were able to acquire. Once we do this we simply combine like terms in order to simplify the expression as much as possible.

4p + 5 + 2p - 3

4p + 2p + 5 - 3

6p - 2

Therefore, the total and simplified expression for the total number of signatures would be 6p - 2

8 0

2 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

3 years ago

In a bag there are 13 red marbles 5 blue marbles and 7green marbles what percent of the marbles are green

Anna71 [15]

13 red, 5 blue, 7 green...for a total of 25

percentage of green ones is : 7/25 = 0.28 = 28% <==

7 0

2 years ago