Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
Answer:
1 whole or 12/12
Step-by-step explanation:
so you go and subtract and you ad what each one equals
10-12=2
9-12=3
3-12=9
---------------
= 1 whole OR 12/12
Hello,
A linear function is a polynomial function of degree 1
(1,2,3,4,5,6,....)
A quadratic function is a polynomial function of degree 2
(1,4,9,16,25,49,64,81,...)
A exponential function is not a polynomial function (we may imagine a infinity degree)
(1,2,4,8,16,32,64,128,256,512,1024,...)
1. 343^(2/3)
3rdrt[(343(343)]
49
2. [2,197^(1/3)]^2
[3rdrt(2,197)]^2
169
3. 729^(2/3)
3rdrt[729(729)]
81
4. (1,000^2)^(1/3)
3rdrt(1,000^2)
100
5. [3rdrt(9261)]^2
441
6. [3rdrt(216^2)]
36
Hope this helps!
Answer:
its 0.45
Step-by-step explanation:
