Step-by-step explanation:
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%error=(6.5g/mol - 7g/mol)/(7g/mol) * 100= 7.14% error
What you are going to do is multiply what you have in parenthesis by two the answer is 2Xsquared and 2Y to the fourth
Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80
![d \times 0.10 + q \times 0.25 = 4.80](https://tex.z-dn.net/?f=d%20%5Ctimes%200.10%20%2B%20q%20%5Ctimes%200.25%20%3D%204.80)
0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
The answer of 74 divided by 8 hope this helps