Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8

=18 sqrt2+15 sqrt2=33 sqrt 2
Answer:
$2,226.96
Step-by-step explanation:
You are going to want to use the compound interest formula, which is shown below.

<em>P = initial balance
</em>
<em>r = interest rate
</em>
<em>n = number of times compounded annually
</em>
<em>t = time
</em>
<em />
First, change 10% into its decimal form:
10% ->
-> 0.1
Now lets plug in the values into the equation:


The final amount after 15 years is $2,226.96