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3 years ago

See screenshots for question and answer choices.

Mathematics

2 answers:

yawa3891 [41]3 years ago

3 0

Answer:

I belive its 300

Step-by-step explanation:

Brainlist?

Elanso [62]3 years ago

3 0

375cm

You work out the area of the rectangle by doing 30x10= 300

Then you work out the area of the triangle (basexheight) divided by 2.
10x15=150
150/2=75

300+75=375.

I’m not sure if this is right but I hope it helps.

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Which equation in slope intercept represents the line that goes through the points (-1, 6) and (1, -2)

Afina-wow [57]

Answer:

D) y=-4x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-6)/(1-(-1))

m=-8/(1+1)

m=-8/2

m=-4

y-y1=m(x-x1)

y-6=-4(x-(-1))

y-6=-4(x+1)

y=-4x-4+6

y=-4x+2

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3 years ago

Let f(x) = ............

34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

Now lets solve for f(-2)

-2^2-3

4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

3 0

3 years ago

What is the significance of a correlation coefficient of 0.88?

AleksandrR [38]

The maximum positive value that the correlation coefficient can have is 1.
Thus, 0.88 is pretty close, indicating a positive slope for the regression line and points lying close to that line.

6 0

3 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago

Please help me with all I need for tomorrow thanks

Vikentia [17]

1. 6
2. 4
3. 5
4. area
5. perimeter
6. 12
7. 16

8.

   .   . _ . _ ._.   .   .
   .   |.   .   .   |._.   .
   .   |.   .   .   .   |. .
   .   |.   .   .   . _|.   .
   .   |. _. _. _|.   .   .

Area = 14

The borders enclose 14 squares that are 1 long and 1 unit wide.

3 0

3 years ago