Answer:
Thus the order of covalent character will be
DG < EG < DF < DE
Explanation:
The electronegativity decides the nature of bond formed between two atoms.
More the difference in electronegativity more the ionic character in the bond formed.
Let us check the electronegativity difference between the elements forming molecules
a) DE :
3.8-3.3 = 0.5
b) DG :
3.8-1.3 = 2.5
c) EG
3.3-1.3 = 2
d) DF
3.8-2.8 = 1.3
So the maximum ionic character will be in DG and minimum in DE
Thus the order of covalent character will be
DG < EG < DF < DE
Answer:
O2 and O3 are allotropes of Oxygen, therefore they have (4) different chemical and physical properties.
Explanation:
Answer:
All of the above processes have a ΔS < 0.
Explanation:
ΔS represents change in entropy of a system. Entropy refers to the degree of disorderliness of a system.
The question requests us to identify the process that has a negative change of entropy.
carbon dioxide(g) → carbon dioxide(s)
There is a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.
water freezes
There is a change in state from liquid to solid. Solid particles are more ordered than liquid particles so this is a negative change in entropy.
propanol (g, at 555 K) → propanol (g, at 400 K)
Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.
This reaction highlights a drop in temperature which means a negative change in entropy.
methyl alcohol condenses
Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.
