Answer:
3 hydrogen bonds.
Explanation:
This is because the urea molecule has an oxygen atom bound with double bonds to the central carbon atom, and this oxygen can form a hydrogen bond with water, as well as both terminal amine groups that can also form a hydrogen bond each because of the lone pair of electrons on the nitrogen group.
Answer:
4.4 moles of water
Explanation:
Propane is C3H8. Is the chemical equation, you wrote C2H8 which is wrong. Type everything properly and give a check before finally posting the question.
The chemical equation that is given, is not properly balanced. The BALANCED equation would be
C3H8 + 5O2 → 3CO2 + 4H2O
From this balanced chemical equation, we see that 5 moles of oxygen produce 4 moles of water.
5 moles of Oxygen → 4 moles of water
1mole of oxygen → 
moles of water
5.5 moles of oxygen → ( × 5.5) moles of water = 4.4 moles of water
∴ The reaction of 5.5 mol of O2 will produce <u>4.4</u> mol of H2O. [Answer:]
A major factor in how the periodic table<span> is organized is the configuration of each </span>element's<span> valence electrons. Because </span>elements<span> in each family have the same number of valence electrons, they tend to have several similar </span>characteristics<span>.</span>
The question is incomplete. The complete question is stated below:
Two point charges are held at the corners of a rectangle as shown in the figure. The lengths of sides of the rectangle are 0.050 m and 0.150 m. Assume that the electric potential is defined to be zero at infinity.
a. Determine the electric potential at corner A.
b. What is the electric potential energy of a +3 µC charge placed at corner A?
Answer / Explanation:
a )V(A) = 1 / 4πe° ( - 5 5x10∧6C / 0.150m + 2x10∧6C / 0.050m )
The answer to the equation above is : = +6.0x10∧4 j/c
b) U(A) = qV(A)= (3.0x10∧6C) (6.0x10∧4 . j/c) =
The answer to the equation above is : =0.18 J
Explanation:
Where V(A) is equivalent to the electric potential
U(A) is equivalent to the electric potential energy
