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3 years ago

22 points! I will mark brainliest if correct, but will report if answer is unrelated pls I need help also have a nice day!

Mathematics

2 answers:

AnnZ [28]3 years ago

7 0

Answer:

Step-by-step explanation:

Area of one triangular face = 0.5(base)(height) = 20 sq cm

Surface area = 4(20) = 80 sq cm

Lena [83]3 years ago

4 0

Answer:

A. $80^2cm\\$

Step-by-step explanation:

Link: https://quizlet.com/140201662/surface-area-and-volume-application-of-surface-area-in-context-flash-cards/

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monday through friday ms.carter ran a total of 25.5 miles.lf she ran the same number of miles all 5 days, how many miles did she

777dan777 [17]

Divide total miles by total days:

25.5 miles / 5 days = 5.1 miles per day.

7 0

4 years ago

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An angle measure 34 less than a complementary angle measure of each angle

FinnZ [79.3K]

Answer:

The unknown angle measures 56

Step-by-step explanation:

<u>Complementary Angles</u>:

Two angles are complementary when they add up to 90 degree.

An angle measure 34 less than a complementary angle. Which means angle one is 34 and angles two is 90 minus 34.

angle one + angle two = 90

34 + angle two = 90

angle two = 90 - 34

angle two = 56

7 0

3 years ago

Step 1: 5x − 2x − 3 = −2 + 17 Step 2: 5x − 2x − 3 = 15 Step 3: 3x − 3 = 15 Which of these is most likely the next step?

strojnjashka [21]

What is the original step?

6 0

3 years ago

Read 2 more answers

Help What is the solution?

VladimirAG [237]

Answer:

The answer is B.) x=1, y=2

Step-by-step explanation:

2(1)+2=4

3(1)+3(2)=9

3 0

3 years ago

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Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . <em>The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.</em>

3 0

3 years ago