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gavmur [86]
3 years ago
7

I need help big time. Will reward BRAINLIEST to BEST answer!!!

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
The slope of the line in simplified form is -18.
Kisachek [45]3 years ago
4 0
The find the equation of a line in any form, you will have to find out the slope first:
m=(y2-y1)/(x2-x1)=(48-12)/(32-34)=-18
the simplified form is the slope-intercept form, so next we need to find the y intercept, 
y=mx+b =>y=-18x+b
Use any of the two given points to find out b: 12=-18(34)+b =>b=624
so the equation is: y=-18x +624
Please double check the calculation by yourself
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What is the approximate area of the circle shown below?
Lynna [10]

Answer:

A. 2827 square cm

Step-by-step explanation:

Diameter of circle = 60 cm

Therefore, radius = 60/2 = 30 cm

Area  \: of  \: circle   \\ = \pi {r}^{2} \\  = 3.14159265\times  {30}^{2}   \\  = 3.14159265 \times 900 \\  = 2,827.43339 \:  {cm}^{2}  \\  = 2827 \:  {cm}^{2}

3 0
3 years ago
Factor x^2 + 10x -18
vovangra [49]
This one is no factor, cant do it
3 0
4 years ago
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt
=-\dfrac{229}3

Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
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Set of odd whole numbers
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Explanation
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Which of the following is a solution to the equation Y= 3x-1
umka21 [38]
Your awnser is B my good sir
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