Look at the graph what type of transformation has occurred

Mathematics

1 answer:

Rom4ik [11]2 years ago

8 0

Wait I’m confused can we at least see the picture

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A hotel claims that 8585% of its customers are very satisfied with its service. complete parts a through d below based on a ran

jek_recluse [69]

We can solve this problem using the binomial distribution. A binomial distribution<span> can be thought of as a success or failure outcome in an experiment or survey that is repeated multiple times.
</span>Probability function of binomial distribution has the following form:
$P= \frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}$
p represents the probability of each choice we want. k is the number of choices we want and n is the total number of choices.
In our case p=0.85, k=5 and n=6.
We can now calculate the answer:
$P= \frac{6!}{5!(6-5)!} 0.85^5(1-0.85)^{6-5}=0.39$
The probability is 39%.
.

7 0

3 years ago

Vera is using her phone. Its battery lifw is down to 2/5 and it drains another 1/9 fraction every hour. How long will her batter

just olya [345]

Battery is down currently = 2/5

Battery drains at the rate of 1/9 every hour.

Remaining battery life of Vera = 1 -2/5 = 3/5

Let y we the number of hours battery will last.

So, 1/9 y = 3/5

y = 27/5

y = 5 + 2/5 hours

y = 5 hrs and 24 mins

So battery will last another 5 hrs and 24 mins.

hope this helps:)

4 0

3 years ago

What is the range of possible sizes for side x?

faust18 [17]

0.5 < x < 16.5 given: Two sides of triangle: 8.0 units and 8.5 units
Measure of third side = x
According to the triangle's inequality,
Sum of any two sides > third side. (i)
Difference between the sides < third side. (ii)
If x is the third side, then
x < 8+8.5 [Using (i)]
i.e. x< 16.5
Also, x > 8.5-8 [Using (ii)]
i.e. x> 0.5
Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.

6 0

2 years ago

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Elan Coil [88]

your answer would be 9 fish are left in the tank

5 0

3 years ago

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Which function below represents the arithmetic sequence 3, 7, 11, 15...?

mr Goodwill [35]

D) f(n) = 3 + 4(n-1)

3 = 1st term
4 = common difference among the terms
n = term number you are looking for.

To check: 3, 7, 11, 15, ...

f(1) = 3 + 4(1-1) = 3 + 4(0) = 3 + 0 = 3
f(2) = 3 + 4(2-1) = 3 + 4(1) = 3 + 4 = 7
f(3) = 3 + 4(3-1) = 3 + 4(2) = 3 + 8 = 11
f(4) = 3 + 4(4-1) = 3 + 4(3) = 3 + 12 = 15

4 0

3 years ago

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