3 years ago

SOMEONE HELP ME ITS DUE IN 30 MINSS !

1 answer:

QveST [7]3 years ago

4 0

Answer:

Step-by-step explanation:

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kramer

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3 years ago

Sati [7]

Let $x,y$ be the two numbers. We have two pieces of information:

$x-y=2$ (the difference between the two numbers is 2)

$xy=224$ (their product is 224)

From the first equation, we can deduce $x=y+2$

If we plug this expression in the second equation, we have

$xy = (y+2)y = 224 \iff y^2+2y-224 =0$

If you solve this equation with the usual quadratic formula you get the solutions

$y=-16,\quad y=14$

So, you have the following couple of solutions, recalling that x is 2 more than y:

$\begin{cases} x = -14\\y=-16\end{cases},\quad\begin{cases} x = 16\\y=14\end{cases}$

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3 years ago

tamaranim1 [39]

it's a i think, hope this helps

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2 years ago

Bad White [126]

Answer:

7.04

Step-by-step explanation:

pls mark me brainliest

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3 years ago