All categories

3 years ago

The pH level of tomato juice is 4.2. What is the hydrogen-ion concentration [H+]| for tomato juice?

Mathematics

1 answer:

garri49 [273]3 years ago

4 0

Given:

pH = 4.2 of tomato

Required:

hydrogen-ion concentration [H+]| for tomato juice

Solution:

The formula for the pH relating hydrogen ion concentration is pH = -log[H+] where H+ is the hydrogen ion concentration. so, substitute the value of pH

pH = -log[H+]

4 = - log[H+]

-4 = log[H+]

10^-4 = [H+]

[H+] = 1x10^-4M

You might be interested in

Write the value of the digit 5 in this number:178.25<br>I

siniylev [52]

Step-by-step explanation:

178.25

The number 5 is in the place of one's so the value of 5 is 5

7 0

3 years ago

What is the area of the circle below?<br> 10 ft

azamat

Answer:

<h3>Circle</h3>

Solve for area

A=π r^2

r =Radius

<h2>You about this first: </h2>

The circumference of a circle is its perimeter or distance around it. It is denoted by C in math formulas and has units of distance, such as millimeters (mm), centimeters (cm), meters (m), or inches (in). It is related to the radius, diameter, and pi using the following equations: C = πd. C = 2πr.

Step-by-step explanation:

Hope it is helpful....

8 0

3 years ago

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

Sarah is planning to fence in her backyard garden. One side of the garden is 34 feet long, another side is 30 feet long, and the

Sonbull [250]

Answer: $393

Step-by-step explanation: (34’+ 30’+67’) x $3.00 = 131 x 3.00 = 393

8 0

3 years ago

Half a number increased by 15 is equal to the sum of 5 and the product of 3 and the number.

son4ous [18]

Answer:

(x/2) + 15 = 5 + 3x

Step-by-step explanation:

Follow the steps in the equation. X is your number. First you halve it, then you add 15. Next, set it equal to the other side. The second side is 5 + (because it is the sum) and 3x (the product of 3 and x means multiply them)

3 0

3 years ago