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IgorC [24]
3 years ago
10

C + 1/4c please help me i need this done now

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0

Answer:

1\frac{1}{4} c

Step-by-step explanation:

c+\frac{1}{4}c

Rewrite the expression

= 1c+\frac{1}{4} c

Add

= 1\frac{1}{4} c

Therefore, c+\frac{1}{4}c is equal to 1\frac{1}{4} c.

I hope this helps!

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lina2011 [118]

\\ \sf\longmapsto \dfrac{1}{x-1}>4

  • Multiply x-1 on both sides

\\ \sf\longmapsto \dfrac{1}{x-1}\times (x-1)> 4(x-1)

\\ \sf\longmapsto 1>4(x-1)

\\ \sf\longmapsto 1> 4x-4

  • Add 4 on both sides

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\\ \sf\longmapsto 5> 4x

  • Divide both sides by 4

\\ \sf\longmapsto \dfrac{5}{4}>x

\\ \sf\longmapsto x< \dfrac{5}{4}

Now

ATQ to the equation \bf \dfrac{1}{x-1} x should be greater than 1 .Because if it becomes 1 then the denominator will be 0 which is impossible.

Hence x>1

Thus

\\ \sf{:}\!\implies 1

Now

\\ \therefore\boxed{\bf x\epsilon \left(1,\dfrac{5}{4}\right)}

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