Answer:
(A) The population's growth rate in equation form is y = (0.016t * 7652) + 7652
(B) y = (0.016t * 7652) + 7652 =
y = (0.016(8) * 7652) + 7652 =
y = (0.128 * 7652) + 7652 =
y = 979.456 + 7652 =
y = 8631.456 (Or About) 8631
Step-by-step explanation:
(A) Y = the total population of the town. 0.016 is 1.6% just in its original form. T = the year in which were trying to find the town's total population. 7652 is the total population of the town in 2016. With this information, the equation reads, The total population of the town (Y) is equal to 16% (0.016) of the current year's population (T) added to 2016's population of 7652. (This last sentence can also be read what is 1.6% of the towns population in the year were trying to find. Because the population is always growing, 1.6% gets multiplied as to scale with the total population in year T)
(B) We just substitute (T) for 2024, or 8 years after 2016 (2024-2016) and simplify the equation we made.
Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
Answer:
After 900 minutes
Step-by-step explanation:
when we convert the velocities of the ships into miles/ min we get
The equations determining the distances of the ships from the port M (set at x=0) are
(for 45mph ship)
(for 36mph ship)
The solution to these equation lie at t= 900 minutes; therefore the two ships will meet 900 minutes after the departure of the first ship.
5(r - 10) = -51
= 5r - 50 = -51
= 5r = -51 + 50
= 5r = -1
= r = -1/5
r = -0.2
