Answer:
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
Step-by-step explanation:
116f) 5 - |p + 6| = -8
|p + 6| = 13
p + 6 = 13 OR p + 6 = -13
p = 7 OR p = -19
In this case, I think you have to plot a point at 7 and -19.
116a) |7x| = 5
7x = 5 OR 7x = -5
x = OR x =
Again, I think you need to plot points at and
.
Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
