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3 years ago

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A bag contains 26 red marbles, 8 white marbles, and 5 gray marbles. You randomly pick out a marble, record its color, and put it

back in the bag. You repeat this process 117 times. How many white or gray marbles do you expect to get?

1 answer:

4vir4ik [10]3 years ago

8 0

Answer:

39

Step-by-step explanation:

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I need help ASAP. I need help can someone explain and can anyone tell me the answer please . I’ll give u anything u want

AleksAgata [21]

<h3>Answers:</h3>

Domain: $(-\infty, \infty)$ which is the set of all real numbers
Range: $[3, \infty)$ which is the set of y values such that $y \ge 3$
x intercepts: none
y intercept: only one y intercept and it is at (0,7) this is ordered pair notation and not interval notation
Interval positive: $(-\infty, \infty)$
Interval negative: none
Interval increasing: $(-2, \infty)$
Interval decreasing: $(-\infty, -2)$
Average rate of change over [-2,0] is 2

=====================================================

Explanation:

The domain is the set of all real numbers. This is because the graph goes on forever to the left and right. We can use any x value we want as an input. There are no restrictions to worry about such as to prevent dividing by zero errors.

To say "all real numbers" in interval notation, we write $(-\infty, \infty)$ which is another way of saying $-\infty < x < \infty$

-------------------

The range in interval notation is $[3, \infty)$ since y = 3 is the smallest y output possible, and we could have larger y values as well. So basically $y \ge 3$ can be used to describe the range without saying much else.

Note the use of a square bracket to include 3 as part of the interval.

-------------------

There are no x intercepts because this graph does not cross the x axis. The lowest point is at (-2,3) so there's no way we could reach y = 0. Put another way, y = 0 is not part of the range so we cannot have any x intercepts.

There is one y intercept and it is at (0,7) where the graph crosses the y axis. For any function, the max number of y intercepts is 1.

-------------------

When it says "interval positive", its asking "which part(s) of the graph are above the x axis?". That would be the entire graph meaning we have the interval $(-\infty, \infty)$ . Every point on this V shaped curve is of the form (x,y) where y is positive.

So this means that we do not have any points with a negative y value, and therefore the answer to "interval negative" is none.

-------------------

Now onto the "interval increasing". This is similar to the previous section, but now we're looking when the graph is going uphill as we read from left to right. This happens on the interval $(-2, \infty)$ or put another way when x > -2.

The graph goes downhill whenever x < -2. So that's why the answer for the "interval decreasing" is $(-\infty, -2)$

-------------------

Note the points (-2,3) and (0,7) are on the V shaped graph. These points have x coordinates of x = -2 and x = 0, which are the endpoints of the interval we're focusing on.

Compute the slope of the line through those two points

m = (y2-y1)/(x2-x1)

m = (7-3)/(0-(-2))

m = (7-3)/(0+2)

m = 4/2

m = 2

The positive slope means the line goes uphill as we read from left to right

The average rate of change on the interval [-2, 0] is the value 2

In other words, we go up 2 units each time we move to the right 1 unit.

8 0

3 years ago

What is the answer to any of these

seraphim [82]

Answer:

1.The chosen topic is not meant for use with this type of problem. Try the examples below.

(

6

,

−

3

)

(

6

,

4

)

(

9

,

7

)

7 0

3 years ago

Find the simple interest paid for 7 years on a $600 loan at 5% per year.

aksik [14]

Answer:

Step-by-step explanation:

200

3 0

2 years ago

A professor went to a website for rating professors and looked up the quality rating and also the "easiness" of the six full-tim

Marat540 [252]

We are asked to determine the correlation factor "r" of the given table. To do that we will first label the column for "Quality" as "x" and the column for "Easiness" as "y". Like this:

Now, we create another column with the product of "x" and "y". Like this:

Now, we will add another column with the squares of the values of "x". Like this:

Now, we add another column with the squares of the values of "y":

Now, we sum the values on each of the columns:

Now, to get the correlation factor we use the following formula:

$r=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)}}$

Where:

$\begin{gathered} \Sigma xy=\text{ sum of the column of xy} \\ \Sigma x=\text{ sum of the column x} \\ \Sigma y=\text{ sum of the column y} \\ \Sigma x^2=\text{ sum of the column x\textasciicircum2} \\ \Sigma y^2=\text{ sum of the column y\textasciicircum2} \\ n=\text{ number of rows} \end{gathered}$

Now we substitute the values, we get:

$r=\frac{\left(6)(70.56)-(25.2)(16.4\right)}{\sqrt{((6)(107.12)-(25.2)^2)((6)(47.82)-(16.4)^2)}}$

Solving the operations:

$r=0.858$

Therefore, the correlation factor is 0.858. If the correlation factor approaches the values of +1, this means that there is a strong linear correlation between the variables "x" and "y" and this correlation tends to be with a positive slope.

7 0

1 year ago

Suppose that 200 students are randomly selected from a local college campus to investigate the use of cell phones in classrooms.

serious [3.7K]

Answer:

It would change to 0.04802

Step-by-step explanation:

from this question we have that n became 400

40% of 400

= 160

p* = 160/400

= 0.4

1 - p* =

= 1 - 0.4

= 0.6

at confidence level,

1 - 0.95

= 0.05

alpha/2 = 0.025

z= 1.96

<u>margin of error. E</u>

= 1.96 x √[(0.4 x 0.6)/400]

= 1.96 x 0.0245

= 0.04802

M.E = 0.04802

6 0

3 years ago