A, D, E and F are all true statements.
When looking for congruence in these type of problems, you have to look for the order of the letters in the original listing. Since they are listed LMN and PQR, this means we have to focus on the placement of those letters. Since L is the first listed in the sequence, it is congruent with P, which is also listed first. M is congruent with Q since they are both in the middle, and N and R are congruent since they are both at the end.
Now to find true statements, you need to make sure everything matches up in the statement.
Let's take A for instance. It states that MN = QR. Now we know M is in the middle and N is at the end. Since Q is in the middle and R is at the end, they match and are therefore true.
You would need to remove (-2, 1)
Answer:
c. Multiple zero is 3; multiplicity is 2
Step-by-step explanation:
The factor is repeated, that is, the factor (
x − 3
) appears twice. The number of times a given factor appears in the factored form of the equation of a polynomial is called the multiplicity. The zero associated with this factor, x = 3
, has multiplicity 2 because the factor (
x − 3
) occurs twice.
Then
Multiple zero is 3; multiplicity is 2.
Answer:
x = 11
Step-by-step explanation:
3(2x-4) = 5x-1
6x + (-12) = 5x + (-1)
add -12 to both sides, subtract 5x from both sides. Simplify.
x=11